Optimal. Leaf size=134 \[ \frac{a^4}{4 d (a-a \sin (c+d x))^2}+\frac{7 a^3}{4 d (a-a \sin (c+d x))}-\frac{a^2 \csc ^2(c+d x)}{2 d}-\frac{2 a^2 \csc (c+d x)}{d}-\frac{31 a^2 \log (1-\sin (c+d x))}{8 d}+\frac{4 a^2 \log (\sin (c+d x))}{d}-\frac{a^2 \log (\sin (c+d x)+1)}{8 d} \]
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Rubi [A] time = 0.148136, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {2836, 12, 88} \[ \frac{a^4}{4 d (a-a \sin (c+d x))^2}+\frac{7 a^3}{4 d (a-a \sin (c+d x))}-\frac{a^2 \csc ^2(c+d x)}{2 d}-\frac{2 a^2 \csc (c+d x)}{d}-\frac{31 a^2 \log (1-\sin (c+d x))}{8 d}+\frac{4 a^2 \log (\sin (c+d x))}{d}-\frac{a^2 \log (\sin (c+d x)+1)}{8 d} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \csc ^3(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x))^2 \, dx &=\frac{a^5 \operatorname{Subst}\left (\int \frac{a^3}{(a-x)^3 x^3 (a+x)} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^8 \operatorname{Subst}\left (\int \frac{1}{(a-x)^3 x^3 (a+x)} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^8 \operatorname{Subst}\left (\int \left (\frac{1}{2 a^4 (a-x)^3}+\frac{7}{4 a^5 (a-x)^2}+\frac{31}{8 a^6 (a-x)}+\frac{1}{a^4 x^3}+\frac{2}{a^5 x^2}+\frac{4}{a^6 x}-\frac{1}{8 a^6 (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=-\frac{2 a^2 \csc (c+d x)}{d}-\frac{a^2 \csc ^2(c+d x)}{2 d}-\frac{31 a^2 \log (1-\sin (c+d x))}{8 d}+\frac{4 a^2 \log (\sin (c+d x))}{d}-\frac{a^2 \log (1+\sin (c+d x))}{8 d}+\frac{a^4}{4 d (a-a \sin (c+d x))^2}+\frac{7 a^3}{4 d (a-a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 1.18508, size = 84, normalized size = 0.63 \[ -\frac{a^2 \left (\frac{14}{\sin (c+d x)-1}-\frac{2}{(\sin (c+d x)-1)^2}+4 \csc ^2(c+d x)+16 \csc (c+d x)+31 \log (1-\sin (c+d x))-32 \log (\sin (c+d x))+\log (\sin (c+d x)+1)\right )}{8 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.141, size = 199, normalized size = 1.5 \begin{align*}{\frac{{a}^{2}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{a}^{2}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+4\,{\frac{{a}^{2}\ln \left ( \tan \left ( dx+c \right ) \right ) }{d}}+{\frac{{a}^{2}}{2\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{5\,{a}^{2}}{4\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{15\,{a}^{2}}{4\,d\sin \left ( dx+c \right ) }}+{\frac{15\,{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{4\,d}}+{\frac{{a}^{2}}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{3\,{a}^{2}}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{3\,{a}^{2}}{2\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.992041, size = 161, normalized size = 1.2 \begin{align*} -\frac{a^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) + 31 \, a^{2} \log \left (\sin \left (d x + c\right ) - 1\right ) - 32 \, a^{2} \log \left (\sin \left (d x + c\right )\right ) + \frac{2 \,{\left (15 \, a^{2} \sin \left (d x + c\right )^{3} - 22 \, a^{2} \sin \left (d x + c\right )^{2} + 4 \, a^{2} \sin \left (d x + c\right ) + 2 \, a^{2}\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{3} + \sin \left (d x + c\right )^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.5414, size = 732, normalized size = 5.46 \begin{align*} -\frac{44 \, a^{2} \cos \left (d x + c\right )^{2} - 40 \, a^{2} - 32 \,{\left (a^{2} \cos \left (d x + c\right )^{4} - 3 \, a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} + 2 \,{\left (a^{2} \cos \left (d x + c\right )^{2} - a^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \sin \left (d x + c\right )\right ) +{\left (a^{2} \cos \left (d x + c\right )^{4} - 3 \, a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} + 2 \,{\left (a^{2} \cos \left (d x + c\right )^{2} - a^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 31 \,{\left (a^{2} \cos \left (d x + c\right )^{4} - 3 \, a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} + 2 \,{\left (a^{2} \cos \left (d x + c\right )^{2} - a^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (15 \, a^{2} \cos \left (d x + c\right )^{2} - 19 \, a^{2}\right )} \sin \left (d x + c\right )}{8 \,{\left (d \cos \left (d x + c\right )^{4} - 3 \, d \cos \left (d x + c\right )^{2} + 2 \,{\left (d \cos \left (d x + c\right )^{2} - d\right )} \sin \left (d x + c\right ) + 2 \, d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27012, size = 169, normalized size = 1.26 \begin{align*} -\frac{4 \, a^{2} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) + 124 \, a^{2} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) - 128 \, a^{2} \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) + \frac{3 \, a^{2} \sin \left (d x + c\right )^{4} + 114 \, a^{2} \sin \left (d x + c\right )^{3} - 173 \, a^{2} \sin \left (d x + c\right )^{2} + 32 \, a^{2} \sin \left (d x + c\right ) + 16 \, a^{2}}{{\left (\sin \left (d x + c\right )^{2} - \sin \left (d x + c\right )\right )}^{2}}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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